You are right that $x$ can take on multiple values, however we need to address the question in the main stem, which asks “Is $x \lt 5$? Based on statement 2, you will find that $x$ can only fall between approximately $-2.8$ and $1.8$. This means that even though $x$ can take multiple values, the answer to the question “Is $x \lt 5$? is always a definite YES. And therefore the statement is sufficient.
I am assuming that you are asking about the case $x=3$ (this wasn’t clear in your question), in this case if we substitute this value in statement 2, you will find that it does not satisfy the statement, which means it is not acceptable as an example. However, if you picked an $x$ value that did satisfy the statement, for example $x=1$, then statement 2 holds true and the answer to the question “Is $x \lt 5$?” is a YES. Similarly, if you kept coming up with examples that satisfy statement 2, then in all cases the answer to the question “Is $x \lt 5$?” will be a definite YES.
The approach I took was to look at cases where $x \gt 5$ by first testing $x=5$, and we notice that this does not satisfy the statement 2, which means that all values of $x$ greater than 5 will not satisfy the statement 2. Therefore, for the statement 2 to hold true $x$ must be less than 5. Therefore the answer to the question “Is $x \lt 5$?” is a definite YES.
In this case, number two have many possible solutions, could be since 1 until -infinite, because the question don’t says if X is a positive number
Hi Jose,
You are right that $x$ can take on multiple values, however we need to address the question in the main stem, which asks “Is $x \lt 5$? Based on statement 2, you will find that $x$ can only fall between approximately $-2.8$ and $1.8$. This means that even though $x$ can take multiple values, the answer to the question “Is $x \lt 5$? is always a definite YES. And therefore the statement is sufficient.
I hope this makes sense.
Dabral
How does statement 2 satisfy for x5 and 9+3>5. So then it doesn’t satisfy both the equation of x<5 and x^2+x<5
How does statement 2 satisfy for x5 and 9+3>5. So then it doesn’t satisfy both the equation of x<5 and x^2+x<5
I am assuming that you are asking about the case $x=3$ (this wasn’t clear in your question), in this case if we substitute this value in statement 2, you will find that it does not satisfy the statement, which means it is not acceptable as an example. However, if you picked an $x$ value that did satisfy the statement, for example $x=1$, then statement 2 holds true and the answer to the question “Is $x \lt 5$?” is a YES. Similarly, if you kept coming up with examples that satisfy statement 2, then in all cases the answer to the question “Is $x \lt 5$?” will be a definite YES.
The approach I took was to look at cases where $x \gt 5$ by first testing $x=5$, and we notice that this does not satisfy the statement 2, which means that all values of $x$ greater than 5 will not satisfy the statement 2. Therefore, for the statement 2 to hold true $x$ must be less than 5. Therefore the answer to the question “Is $x \lt 5$?” is a definite YES.